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Trigonometry · real student question

Evaluate arctan(15/66.67), giving the answer in both degrees and radians.

Question

Evaluate

arctan⁡ ⁣(1566.67)\arctan\!\left(\frac{15}{66.67}\right)

giving the answer in both degrees and radians.

Step-by-step solution

  1. Understand what the inverse tangent returns. arctan⁡t\arctan t is the angle θ\theta with tan⁡θ=t\tan\theta=t and −90∘<θ<90∘-90^{\circ}<\theta<90^{\circ}. Unlike arcsin⁡\arcsin and arccos⁡\arccos, its domain is all real numbers, so no range check on the input is needed. In applied work this shape — arctan⁡oppositeadjacent\arctan\frac{\text{opposite}}{\text{adjacent}} — is how a right triangle's acute angle is recovered from its two legs.

  2. Reduce the ratio to a single decimal. Do the division before the trig function:

    1566.67=0.2249887…≈0.2250\frac{15}{66.67}=0.2249887\ldots\approx0.2250

    so the task becomes arctan⁡(0.2250)\arctan(0.2250).

  3. Predict the size of the answer. Since tan⁡0∘=0\tan0^{\circ}=0 and tan⁡45∘=1\tan 45^{\circ}=1, a tangent of only 0.2250.225 must give an angle well under 45∘45^{\circ} — and because tan⁡θ≈θ\tan\theta\approx\theta in radians for small angles, expect roughly 0.2250.225 rad ≈13∘\approx13^{\circ}. This estimate is exactly what catches a calculator left in the wrong angle mode.

  4. Evaluate in radians.

    arctan⁡(0.2249887)=0.2213037 rad≈0.2213 rad\arctan(0.2249887)=0.2213037\ \text{rad}\approx0.2213\ \text{rad}

    As predicted, slightly below the input 0.2250.225, since tan⁡θ>θ\tan\theta>\theta for small positive θ\theta.

  5. Convert to degrees. Multiply by 180π\dfrac{180}{\pi}:

    0.2213037×180π=12.6798∘≈12.68∘0.2213037\times\frac{180}{\pi}=12.6798^{\circ}\approx12.68^{\circ}

  6. Verify by going backwards. tan⁡(12.6798∘)=0.224989\tan(12.6798^{\circ})=0.224989, which matches 1566.67=0.224989\tfrac{15}{66.67}=0.224989 to six decimals ✓.

Answer

arctan⁡ ⁣(1566.67)≈0.2213 rad≈12.68∘\arctan\!\left(\frac{15}{66.67}\right)\approx 0.2213\ \text{rad}\approx 12.68^{\circ}

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