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Calculus · real student question

Evaluate the indefinite integral of 25 x^(3/2) with respect to x.

Question

Evaluate the indefinite integral ∫25x3/2 dx.\int 25x^{3/2}\,dx.

Step-by-step solution

  1. Pull the constant out. Constants ride through an integral untouched: ∫25x3/2 dx=25∫x3/2 dx.\int 25x^{3/2}\,dx=25\int x^{3/2}\,dx.

  2. Apply the power rule with n=32n=\tfrac32. The rule ∫xn dx=xn+1n+1+C\displaystyle\int x^{n}\,dx=\frac{x^{n+1}}{n+1}+C works for any n≠−1n\ne-1, fractional exponents included. Here n+1=32+1=52.n+1=\frac32+1=\frac52.

  3. Divide by the new exponent. 25∫x3/2 dx=25⋅x5/252+C.25\int x^{3/2}\,dx=25\cdot\frac{x^{5/2}}{\tfrac52}+C. Dividing by 52\tfrac52 is the same as multiplying by 25\tfrac25, which is where students most often slip.

  4. Multiply out the constant. 25⋅25=1025\cdot\tfrac25=10, so the antiderivative is 10x5/2+C10x^{5/2}+C.

  5. Check by differentiating. ddx(10x5/2)=10⋅52x3/2=25x3/2\dfrac{d}{dx}\left(10x^{5/2}\right)=10\cdot\tfrac52 x^{3/2}=25x^{3/2}, which is the original integrand.

Answer

10x5/2+C10x^{5/2}+C

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