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Algebra · real student question

Solve for p: 6(5 + p) = 7(p + 6) - 5.

Question

Solve for pp:

6(5+p)=7(p+6)−56(5+p)=7(p+6)-5

Step-by-step solution

  1. Expand the left side. Distribute the 66 over both terms:

    6(5+p)=30+6p6(5+p)=30+6p

  2. Expand the right side and fold in the loose constant. Distribute the 77, then subtract 55:

    7(p+6)−5=7p+42−5=7p+377(p+6)-5=7p+42-5=7p+37

    Combining 42−542-5 now, before moving anything across the equals sign, keeps the next step to a single operation.

  3. Write the simplified equation.

    30+6p=7p+3730+6p=7p+37

    Both sides contain pp, so the terms must be gathered before pp can be read off.

  4. Eliminate the smaller p term. Subtracting 6p6p (rather than 7p7p) leaves the variable with coefficient +1+1, so no division will be needed at the end:

    30=p+3730=p+37

  5. Isolate p. Subtract 3737 from both sides:

    30−37=p⟹p=−730-37=p\qquad\Longrightarrow\qquad p=-7

  6. Verify in the original equation. Left: 6(5−7)=6(−2)=−126(5-7)=6(-2)=-12. Right: 7(−7+6)−5=7(−1)−5=−7−5=−127(-7+6)-5=7(-1)-5=-7-5=-12 ✓. Both sides give −12-12, so p=−7p=-7 is confirmed.

Answer

p=−7p=-7

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