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Trigonometry · real student question

Evaluate cos(225 degrees), giving an exact value.

Question

Evaluate

cos⁡225∘\cos 225^\circ

giving an exact value.

Step-by-step solution

  1. Locate the angle's quadrant. 180∘<225∘<270∘180^\circ<225^\circ<270^\circ, so the terminal side lies in the third quadrant, where both coordinates on the unit circle are negative. Cosine reads the xx-coordinate, so the answer must be negative.

  2. Find the reference angle. In the third quadrant the reference angle is the angle past 180∘180^\circ:

    225∘−180∘=45∘225^\circ-180^\circ=45^\circ

  3. Apply the third-quadrant identity. Equivalently cos⁡(180∘+θ)=−cos⁡θ\cos(180^\circ+\theta)=-\cos\theta:

    cos⁡225∘=cos⁡(180∘+45∘)=−cos⁡45∘\cos 225^\circ=\cos(180^\circ+45^\circ)=-\cos 45^\circ

  4. Substitute the special-angle value.

    cos⁡45∘=22⟹cos⁡225∘=−22\cos 45^\circ=\frac{\sqrt2}{2}\quad\Longrightarrow\quad \cos 225^\circ=-\frac{\sqrt2}{2}

  5. Check numerically and against the sign rule. −22≈−0.7071068-\tfrac{\sqrt2}{2}\approx-0.7071068, and a direct evaluation of cos⁡225∘\cos 225^\circ gives −0.7071068-0.7071068 ✓\checkmark. The negative sign matches the third-quadrant prediction, and 225∘225^\circ in radians is 5π4\tfrac{5\pi}{4}, the point (−22,−22)\left(-\tfrac{\sqrt2}{2},-\tfrac{\sqrt2}{2}\right) on the unit circle.

Answer

cos⁡225∘=−22≈−0.7071\cos 225^\circ=-\frac{\sqrt{2}}{2}\approx-0.7071

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