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Arithmetic · real student question

Find x if (19x + 83) divided by 7 equals 8 squared minus 5 squared.

Question

Find xx if (19x+83):7=82−52(19x+83):7 = 8^2-5^2.

Step-by-step solution

  1. Evaluate the right-hand side first. 82−52=64−25=398^2-5^2 = 64-25 = 39. The difference-of-squares identity gives the same thing faster: (8−5)(8+5)=3⋅13=39(8-5)(8+5) = 3\cdot13 = 39.

  2. Rewrite the equation. (19x+83):7=39.(19x+83):7 = 39. The unknown is inside the dividend, so the inverse operation is multiplication.

  3. Undo the division by 7. 19x+83=39⋅7=273.19x+83 = 39\cdot7 = 273.

  4. Isolate the x-term. 19x=273−83=190.19x = 273-83 = 190.

  5. Divide by 19. x=19019=10,x = \frac{190}{19} = 10, since 19⋅10=19019\cdot10 = 190 exactly.

  6. Check in the original equation. 19(10)+83=190+83=27319(10)+83 = 190+83 = 273, and 273:7=39273:7 = 39, which equals 82−528^2-5^2. The answer is confirmed.

Answer

x=10x = 10

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