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Algebra · real student question

The function f(x) = |x| + 10 is translated 8 units left and 2 units down. Write the new function.

Question

The graph of

f(x)=∣x∣+10f(x)=|x|+10

is translated 88 units left and 22 units down. Write the equation of the new function.

Step-by-step solution

  1. Separate the two kinds of shift. Horizontal and vertical translations obey different rules, and mixing them up is the standard mistake:

    shift h right: x↦x−h (inside),shift k up: +k (outside)\text{shift } h \text{ right: } x\mapsto x-h\ \text{(inside)},\qquad \text{shift } k \text{ up: } +k\ \text{(outside)}

    Inside the function the sign is opposite to the direction of travel; outside it matches.

  2. Apply the horizontal shift. Moving 88 units left means h=−8h=-8, so xx is replaced by x−(−8)=x+8x-(-8)=x+8:

    ∣x∣+10 ⟶ ∣x+8∣+10|x|+10\ \longrightarrow\ |x+8|+10

    The +8+8 inside moving the graph left is exactly the counter-intuitive part: the vertex was at x=0x=0 and is now at x=−8x=-8.

  3. Apply the vertical shift. Moving 22 units down means subtracting 22 from the whole output:

    ∣x+8∣+10−2=∣x+8∣+8|x+8|+10-2=|x+8|+8

  4. Track the vertex to confirm. The original vertex sits at (0,10)(0,10). Shifting 88 left and 22 down should land it at (−8,8)(-8,8). From the new formula, ∣x+8∣|x+8| is smallest when x=−8x=-8, where the value is 0+8=80+8=8 - vertex (−8,8)(-8,8) ✓.

  5. Check a second point. In the original, f(0)=10f(0)=10. That point (0,10)(0,10) should move to (−8,8)(-8,8), already confirmed; and the original point (8,18)(8,18) should move to (0,16)(0,16). The new function gives ∣0+8∣+8=16|0+8|+8=16 ✓.

Answer

f(x)=∣x+8∣+8f(x)=|x+8|+8

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