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Algebra · real student question

Simplify 3/2 times a plus a^2 minus 4/5 times a minus 3 times a^2.

Question

Simplify

32a+a2−45a−3a2.\frac{3}{2}a+a^{2}-\frac{4}{5}a-3a^{2}.

Step-by-step solution

  1. Sort the terms by degree before touching the fractions. There are two a2a^2 terms and two aa terms; they never mix, so handle each family separately:

    (a2−3a2)+(32a−45a).\left(a^{2}-3a^{2}\right)+\left(\frac{3}{2}a-\frac{4}{5}a\right).

  2. Combine the quadratic terms. The first has an invisible coefficient of 11:

    1a2−3a2=−2a2.1a^{2}-3a^{2}=-2a^{2}.

  3. Give the linear coefficients a common denominator. The denominators 22 and 55 have LCD 1010:

    32=1510,45=810.\frac{3}{2}=\frac{15}{10},\qquad \frac{4}{5}=\frac{8}{10}.

  4. Subtract the linear coefficients.

    1510−810=710,\frac{15}{10}-\frac{8}{10}=\frac{7}{10},

    so the linear term is 710a\tfrac{7}{10}a, or equivalently 0.7a0.7a.

  5. Write the simplified expression. Conventionally in descending powers:

    −2a2+710a.-2a^{2}+\frac{7}{10}a.

    It could also be factored as a(710−2a)a\left(\tfrac{7}{10}-2a\right), but as written it is already fully simplified.

  6. Check with a value. At a=10a=10 the original is 15+100−8−300=−19315+100-8-300=-193, and the answer gives −2(100)+710(10)=−200+7=−193-2(100)+\tfrac{7}{10}(10)=-200+7=-193 ✓.

Answer

−2a2+710a-2a^{2}+\frac{7}{10}a

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