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Algebra · real student question

Expand and simplify (x + 2)(x - 3).

Question

Expand and simplify

(x+2)(x−3)(x+2)(x-3)

Step-by-step solution

  1. Distribute the first bracket term by term. Each term of (x+2)(x+2) multiplies the whole of (x−3)(x-3):

    x(x−3)+2(x−3)x(x-3) + 2(x-3)

  2. Expand both products.

    x2−3x+2x−6x^2 - 3x + 2x - 6

    These four terms are the F, O, I and L of the FOIL mnemonic: x⋅xx\cdot x, x⋅(−3)x\cdot(-3), 2⋅x2\cdot x, 2⋅(−3)2\cdot(-3).

  3. Combine the two middle terms.

    −3x+2x=−x⟹x2−x−6-3x + 2x = -x \quad\Longrightarrow\quad x^2 - x - 6

    The middle coefficient is the sum of the two constants, 2+(−3)=−12 + (-3) = -1, and the last term is their product, 2×(−3)=−62 \times (-3) = -6 — the shortcut worth remembering for monic quadratics.

  4. Read off the structure of the result. x2−x−6x^2 - x - 6 has roots x=−2x = -2 and x=3x = 3, exactly the values that make each original factor vanish. Its graph is an upward parabola crossing the axis at those two points, with vertex at x=12x = \tfrac12.

  5. Check numerically at x = 5. The factored form gives (7)(2)=14(7)(2) = 14; the expanded form gives 25−5−6=1425 - 5 - 6 = 14. At x=−1x = -1: (1)(−4)=−4(1)(-4) = -4 and 1+1−6=−41 + 1 - 6 = -4. Both agree.

Answer

x2−x−6x^2 - x - 6

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