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Algebra · real student question

Expand the product of 5x² + 6x and 9x² - 8.

Question

Expand:

(5x2+6x)(9x2−8)(5x^2+6x)(9x^2-8)

Step-by-step solution

  1. Count the products before starting. Two terms times two terms gives 2×2=42\times 2=4 products. Keeping track of the expected count is the simplest guard against dropping one.

  2. Distribute the first term.

    5x2(9x2−8)=45x4−40x25x^2(9x^2-8)=45x^4-40x^2

    Exponents add when multiplying while coefficients multiply: x2⋅x2=x4x^2\cdot x^2=x^4 and 5⋅9=455\cdot 9=45, not 525^{2}.

  3. Distribute the second term.

    6x(9x2−8)=54x3−48x6x(9x^2-8)=54x^3-48x

  4. Add the two results and order by degree.

    45x4−40x2+54x3−48x=45x4+54x3−40x2−48x45x^4-40x^2+54x^3-48x=45x^4+54x^3-40x^2-48x

    The four terms have degrees 4,3,2,14,3,2,1 — all different — so there are no like terms to combine. Any "simplification" beyond reordering would be an error.

  5. Check at x=1x=1, and note the hidden common factor. The original is (5+6)(9−8)=11(5+6)(9-8)=11, and the expansion gives 45+54−40−48=1145+54-40-48=11 ✓. Every term contains an xx, so the answer also factors as x(5x+6)(9x2−8)x(5x+6)(9x^2-8) — a useful form if the next step is to solve for the roots.

Answer

(5x2+6x)(9x2−8)=45x4+54x3−40x2−48x(5x^2+6x)(9x^2-8)=45x^4+54x^3-40x^2-48x

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