calculus

Implicit Differentiation

Implicit differentiation finds dy/dx when y is defined implicitly by an equation (like x²+y²=25), without first solving for y.

Implicit differentiation finds dydx\frac{dy}{dx} when yy is defined implicitly by an equation, without first solving for yy explicitly. It's especially useful when solving for yy is hard or impossible.

Procedure: differentiate both sides of the equation with respect to xx, treating yy as a function of xx (so each yy term gets a dydx\frac{dy}{dx} via chain rule), then solve for dydx\frac{dy}{dx}.

Example: For x2+y2=25x^2 + y^2 = 25 (a circle):

  1. Differentiate both sides: 2x+2ydydx=02x + 2y \frac{dy}{dx} = 0.
  2. Solve: dydx=xy\frac{dy}{dx} = -\frac{x}{y}.

This gives the slope at any point on the circle without needing y=±25x2y = \pm\sqrt{25 - x^2}.

Implicit differentiation is the standard tool for:

  • Tangent lines to curves that are not graphs of functions.
  • Related rates problems (water filling a cone, ladder sliding down a wall).
  • Differentiating inverse functions (the derivation of ddxarcsinx=11x2\frac{d}{dx}\arcsin x = \frac{1}{\sqrt{1-x^2}} uses it).
  • Solving differential equations and curves of constant property (level curves).